In The Given Circuit With Steady Current, Differential Equations: Used to describe the complete response of circuits involving energy storage elements. . Solution: In steady state condition, no current will flow through the capacitor C. Then by using Kirchhoff’s voltage law (KVL), the voltage drops around the circuit are given as: The current now flowing around the circuit is called the Charging Current and is found by using Ohms law as: i = Vs/R. Jun 10, 2025 ยท Concepts Capacitor behavior in DC circuits, steady state DC current, capacitor acts as open circuit at steady state, voltage division Explanation In steady state (long time after the circuit is powered), a capacitor behaves like an open circuit in a DC circuit because the current through the capacitor is zero (capacitor is fully charged). In steady state condition ,no current will flow through the capacitor C. the , > < br to of and a : " in you that i it he is was for - with ) on ( ? his as this ; be at but not have had from will are they -- ! all by if him one your or up her there can so out them an my when she 1 no which me were we then 2 into 5 do what get go their now said would about time quot ] [ more only back been who down like has some --- just 3 Inductor Behavior: In steady state, an inductor acts as a short circuit for DC, while it stores energy during transients. Find the potential difference between points B and C. current in the outer circuit, `i= (2V-v)/ (2R+R)=V/ (3R)` Potential difference between A and B `V_A-V-V-iR=V_B` `V_B-V_A=iR= (v/ (3R))R=V/3`Note: In this problem charged stored in the capacitor can also be asked, which is equal to `q=cV/3` with possitive charge on b sides and negative on A side because `V_Bgt V_A` In the given circuit, with steady current, calculate the potential drop across the capacitor and the charge stored in it. In the given figure, a steady current I flows through the circuit when points A and C are connected by a wire of negligible resistance. nzfsxb, mg, o70p, pcm, r55, c86bl, a14y6, keuqws, cabf, 2jdy4p,